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Found 28 results

  1. Curved surface area of a cylinder = 2 x pie x r xh Where r = radius of base, h = height of cylinder Total surface area of a cylinder = (2 x pie x r x h) + (2 x pie x r^2) Volume of a cylinder = pie x r^2 x h Surface area of sphere = 4 x pie x r^2 where r= radius of sphere, d= diameter of sphere Volume of a sphere = 4/3 x pie x r^3
  2. Area of base of a cone = pie x r^2 Curved surface area of a cone = pie x r x L Where r = radius of base , l = slanting height of cone Total surface area of a cone = (pie x r x L) + pie x r^2 Volume of right circular cone = 1/3 x pie x r^2 x h Where r = radius of base of cone , h= height of the cone (perpendicular to base) Surface area of triangular prism = (P × height) + (2 × area of triangle) Where p = perimeter of base Surface area of polygonal prism = (Perimeter of base × height ) + (Area of polygonal base × 2) Lateral surface area of prism = Perimeter of base × height Volume of Triangular prism = Area of the triangular base × height
  3. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp_11 = question paper 11 qp_12 = question paper 12 qp_13 = question paper 13 qp_21 = question paper 21 qp_22 = question paper 22 qp_23 = question paper 23 4024_s10_qp_11.pdf 4024_s10_qp_12.pdf 4024_s10_qp_13.pdf 4024_s10_qp_21.pdf 4024_s10_qp_22.pdf 4024_s10_qp_23.pdf
  4. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w09_qp_1.pdf 4024_w09_qp_2.pdf
  5. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s09_qp_1.pdf 4024_s09_qp_2.pdf
  6. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w08_qp_1.pdf 4024_w08_qp_2.pdf
  7. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s08_qp_1.pdf 4024_s08_qp_2.pdf
  8. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w07_qp_1.pdf 4024_w07_qp_2.pdf
  9. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s07_qp_1.pdf 4024_s07_qp_2.pdf
  10. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w06_qp_1.pdf 4024_w06_qp_2.pdf
  11. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s06_qp_1.pdf 4024_s06_qp_2.pdf
  12. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w05_qp_1.pdf 4024_w05_qp_2.pdf
  13. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s05_qp_1.pdf 4024_s05_qp_2.pdf
  14. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w04_qp_1.pdf 4024_w04_qp_2.pdf
  15. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s04_qp_1.pdf 4024_s04_qp_2.pdf
  16. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_w03_qp_1.pdf 4024_w03_qp_2.pdf
  17. Past paper paper code: 4024 subject: Mathematics paper type: Question paper NOTE qp1 = question paper 1 qp2 = question paper 2 4024_s03_qp_1.pdf 4024_s03_qp_2.pdf
  18. NOTE: L=LENGTH B=BREATH R=RADIUS D= DIAMETER ^2=SQUARE Area of a Circle (A) = pie x radius^2 / pie x diameter^2 x 1/4 Where r = radius of the circle and d = diameter of the circle. Circumference of a Circle = 2 x pie x radius = pie x diameter r= radius of circle d= diameter of circle Total surface area of cuboid = 2( LB + LH + BH) where l= length , b=breadth , h=height Total surface area of cuboid = 6(length)^2 where l= length length of diagonal of cuboid = Under Root( L^2 + B^2 + H^2) length of diagonal of cube = Under root(3 x length) Volume of cuboid = L x B x H Volume of cube = L x L x L
  19. NOTE: L=LENGTH B=BREATH H=HEIGHT ^2=SQUARE Area of trapezium (A) = 1/2(sum of parallel sides) x H Perimeter of a trapezium (P) = Sum of outer region Area of rhombus (A) = 1/2 x product of diagonal Perimeter of a rhombus (P) = length x 4 where l = length of a side Area of quadrilateral (A) = 1/2 × Diagonal × (Sum of offsets) Area of a Kite (A) = 1/2 × product of it’s diagonals Perimeter of a Kite (A) = 2 × Sum on non-adjacent sides
  20. NOTE: L=LENGTH B= BREATH H=HEIGHT ^2= SQUARE 1. Area of rectangle = L x B 2. Perimeter of a rectangle = 2(L) + 2(B) 3. Area of a square = L x L = L^2 4. Perimeter of a square = Sum of outer region = 4L 5. Area of a parallelogram(A) = L X H HEIGHT IS THE STRAIGHT HEIGHT , NOT THE SLANT HEIGHT 6. Perimeter of a parallelogram (P) = 2(L) + 2(B) 7. Area of a triangle (A) = 1/2 x Base x Height
  21. Q1) 77 divided by 7 = Ans) 11 Q2) 99 divided by 9= Ans) 11 Q3) 72 divided by 6= Ans) 12 Q4) 63 divided by 9= Ans) 9 Q5) 84 divided by 7= Ans) 12
  22. logarithm 1) Logarithm of a finite non-zero number ‘a’ to a base ‘a’ is equals to a. Zero b. One c. Infinite d. None of these 2) Logarithm of 1 to any finite base is: a. Zero b. One c. Infinite d. None of these 3) If 3log(36/25) + log(6/27)^3 – 2log(16/125) a. 2log2 b. 1 c. Log2 d. None of these 4) Log49(7)½ + log25(5)½ -log4(2)½ / log 17.5 a. 5 b. 2 c. 5/2 d. 3/2 5) log₃ a= 2 . then a equals to a. 3 b. 2 c. 9 d. None of these
  23. PROBABILITY 1) An unbiased die is rolled once, what is the probability of obtaining an even number or a prime number a. 1/2 b. 2/3 c. 1/4 d. 1 e. 5/6 2) An unbiased die is rolled once , what is the probability of obtaining an even number or odd number a. 1/6 b. 2/6 c. 4/6 d. 3/6 e. 1 3) 1/5 is the probability that David will solve a certain problem. 1/4 is the probability that John will solve that problem. If both boys work separately , what is the probability that both will solve the problem a. 1/10 b. 1/5 c. 1/4 d. 1/20 e. 1 4) 4/10 is the probability that Bella will be alive in next 30 years, 8/10 is the probability that Linda will be alive in next 30 years. What is the probability that both will be alive in next 30 years a. 0.22 b. 0.26 c. 0.32 d. 0.39 e. 0.4 5) From a bag containing 4 white and 5 black balls, a man draws 3 balls at random. What is the probability of drawing 3 black balls a. 5/42 b. 16/19 c. 12/14 d. 1 e. 0
  24. Muzzamil

    Probability

    PROBABILITY 1) A die is rolled once , the probability of obtaining a number more than 1 is a. 1/6 b. 5/6 c. 1/5 d. 4/6 2) Two dice are rolled once , what is the probability of obtaining an event with 0 difference a. 1/6 b. 3/6 c. 1/36 d. 6/36 3) A coin is tossed ,what is the probability of obtaining “ no tails” a. 1/2 b. 1 c. 0 d. 1/4 4) A n unbiased coin is tossed twice , what is the probability of obtaining at most two tails a. 1/2 b. 1 c. 1/4 d. 3/4 5) An unbiased coin is tossed thrice , what is probability of obtaining less than three heads a. 7/8 b. 1/8 c. 1/4 d. 1
  25. WORD PROBLEMS 1. A plastic film making machine can produce 75 rolls of plastic in an hour. How many rolls of plastic can be produced by the machine in 24-hour period? Flexo plastics has 15 of these machine. How many rolls of plastic can be produced if all 15 machines operate for 24 hours? a) 1900 and 27000 b) 1800 and 27000 c) 1800 and 28000 d) 1700 and 28000 2. David’s electronic is overstocked with 456 USB cables and sells them at a Rs.4 loss. What is his total loss on the sales? a) Rs.1284 b) Rs.1824 c) Rs.1428 d) Rs.1248 3. University trailer sales company sold 352 utility trailers during a recent year. If the gross annual sales for the company was Rs.324,800 , the average selling price for each trailer is : a) Rs.293 ( nearly) b) Rs.392 (nearly) c) Rs.922 (nearly) d) Rs.923(nearly) 4. Industrialized nations have 793 TV sets per thousand people. If this is 9 times as may TVs per thousand people as there are in the undeveloped nations , the numbers of TVs per thousand people in the underdeveloped nations are: a) 88 (nearly) b) 87 (nearly) c) 89(nearly) d) 90(nearly) 5. The united Arab Emirates has the highest rate of cellular phones in the world. The United States ranks 72nd in the world in cellular phone use with approx. 850 phones per 1000 people. The fraction of US people that have phones in lowest terms is: a) 20/17 b) 30/17 c) 17/30 d) 17/20
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